HackerRank: Java If-Else Solution

problem 1:

Given an integer, , perform the following conditional actions:

• If  is odd, print Weird
• If  is even and in the inclusive range of  to , print Not Weird
• If  is even and in the inclusive range of  to , print Weird
• If  is even and greater than , print Not Weird

import java.io.*;

import java.math.*;

import java.security.*;

import java.text.*;

import java.util.*;

import java.util.concurrent.*;

import java.util.regex.*;

public class Solution {

    private static final Scanner scanner = new Scanner(System.in);

    public static void main(String[] args) {

        int n = scanner.nextInt();

        scanner.close();

       

        if (n%2 != 0){

            System.out.println("Weird");

        } else {

            if(n >= 2 && n <= 5){

                System.out.println("Not Weird");

            } else if(n >= 6 && n <= 20){

                System.out.println("Weird");

            } else if(n >= 20){

                System.out.println("Not Weird");

            }

           

           

        }

    }

}

Output: -